-
Batch fermentation of glucose to ethanol yields a productivity of 4.5 g1–1 hl–1. If the yeast cell concentration in the fermentation brought is 5% (v/v) and the intracellular NAD/NADH concentration in the yeast cells in 10 µM the cycling rate of NAD+ ⇔ NADH will be
-
- 50,000 cycles hr–1
- 20,000 cycles hr–1
- 100 cycles hr–1
- None of these
Correct Option: B
P = 4.5 gm/l.hr Ethanol production yeast cell conc.(X) = 5% v/v
NAD+/NADH ceme in yeast cell = 10 µm (m = ml/lit)
= (me/ωt) the cycling rate of NAD+ ⇌ NADH will be.
X = | ml in 1 liter of broth | |
100 |
NAD+/NADH = 10–5 ml/lit.
ml/lit = 10-5 ml/lit | = cycle rate | |||
100 | unit time |

Total NAD+/NADH conc = 5 × 10–5(v/v)
Now, cycle rate = | ![]() | ![]() | cycle / hr = 20,000 cycle/hr. | |
5 × 10-5 |