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50 Hectare of residential sector has 65% buildable area. The FAR of the buildable area is 1.5. Within the residential sector, 60% of dwelling units are of area 100 m2 each and 40% of the dwelling units are of area 80 m2 each. The gross residential density, in dwelling units per Hectare, would be _______.
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- 115 to 117
- 35 to 55
- 75 to 97
- 105 to 107
Correct Option: D
Let, N = Total no. of Dwelling units.
FAR = 1.5 (given)
So, Total buildable area = 50 Hectare × 65% × 1.5 FAR = (50 × 0.65 × 1.5) Hectare = (50 × 0.65 × 1.5 × 10000) m2
As per question, 0.6N × 100 m2 + 0.4N × 80 m2 = total buildable area
So, 0.6N × 100 m2 + 0.4N × 80 m2 = (50 × 0.65 × 1.5 × 10000) m2
By solving above equation, we get N = 5300
| The gross residential density, in dwelling units per Hectare = | = 106 | |
| 50 |
