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A polymerase chain reaction was performed beginning with 400 template DNA molecules in a 100 µl reaction. After 20 cycles of polymerase chain reaction, how many molecules of the amplified product will be present in O.1µl of reaction ?
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- 2.19 × 104
- 4.19 × 104
- 2.19 × 105
- 4.19 × 105
Correct Option: D
In PCR, the template DNA after ‘n’ cycle = (original DNA) × 2n
= 400 × 220
But, this is amount in 100µl. In 0.1 µl we have,
| = | = 4.194304 × 105 | |
| 100 |
