16. What is the output of this program?
    

    #include <iostream>
        using namespace std;
        int main() 
        {
            int num = 6;
            int* ptr = #
            cout << sizeof(ptr);
            return 0;
        }
    

1. 1. 2

   
   
   

   2. 4

   
   
   

   3. 6

   
   
   

   4. 8

   
   
   

   5. Depends on compiler

   
   
   

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1. View Hint View Answer Discuss in Forum

   NA

   Correct Option: A

   The size of a data type mainly depends on compiler only.

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17. What is the output of this program?
    

    #include  <iostream>
        using namespace std;
        int main()
        {
            double array[] = {3.0, 5.0, 6.0, 4.0};
            double *p = (array + 3);
            cout << *p << endl;   
            cout << array << endl;  
            cout << *(array + 2) << endl;
            cout << *(array) << endl;  
            cout << *array + 6 << endl;  
            return 0;
        }
    

1. 1. 4
      0x7ffd1eb06bc0
      6
      3
      9

   
   
   

   2. 4
      6
      3
      9
      0x7ffd1eb06bc0

   
   
   

   3. 6
      3
      9
      0x7ffd1eb06bc0

   
   
   

   4. 3
      9
      0x7ffd1eb06bc0
      6
      4

   
   
   

   5. None of these

   
   
   

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1. View Hint View Answer Discuss in Forum

   NA

   Correct Option: A

   In this program, We are printing the values that are pointed by pointer and also the dereference operator.

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18. What does the dereference operator will return?

1. 1. lvalue equivalent to the value at the pointer address

   
   
   

   2. it will return nothing

   
   
   

   3. rvalue equivalent to the value at the pointer address

   
   
   

   4. All of above

   
   
   

   5. None of these

   
   
   

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1. View Hint View Answer Discuss in Forum

   NA

   Correct Option: C

   It operates on a pointer variable, and returns an l-value equivalent to the value at the pointer address.

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