Communication miscellaneous
- A signal x (t) = 100 cos (2π × 103) t is ideally sample with sampling period of 50 μ sec and then passed through an ideal low-pass filter with cut-off frequency of 15 kHz.
Which of the following frequencies is/are present at the filter output?
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Given x(t) = 100 cos (24π × 103t)
Hence fm = 12 kHzfs = 1 = 1 T 50 × 10−6 = 1000 × 103 = 20 kHz 50
given that the cut-off frequency of a LPF is 15 kHz. Therefore, the frequencies passed through LPF are fm and fs – fm i.e., 12 kHz and 8 kHz, since given that LPF cut-off frequency 15 kHz.
Hence alternative (D) is the correct choice.Correct Option: D
Given x(t) = 100 cos (24π × 103t)
Hence fm = 12 kHzfs = 1 = 1 T 50 × 10−6 = 1000 × 103 = 20 kHz 50
given that the cut-off frequency of a LPF is 15 kHz. Therefore, the frequencies passed through LPF are fm and fs – fm i.e., 12 kHz and 8 kHz, since given that LPF cut-off frequency 15 kHz.
Hence alternative (D) is the correct choice.
- The frequency generated by each decade in a direct frequency synthesizer is much higher than the frequency shown; this is done to—
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NA
Correct Option: A
NA
- Indicate the false statement. Noting that no carrier is transmitted with J3E, we see that—
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NA
Correct Option: B
NA
- One of the following cannot be used to demodulate SSB—
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NA
Correct Option: C
NA
- A low ratio of the ac to the dc load impedance of a diode detector results in—
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A low ratio of the ac to the dc load impedance of a diode detector results in negative-peak clipping.
Correct Option: C
A low ratio of the ac to the dc load impedance of a diode detector results in negative-peak clipping.