Variables
- What will be the output of the following C code?
#include <stdio.h>
int num;
void main()
{
printf("%d", num);
}
-
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NA
Correct Option: B
0
- What will be the output of the following C code?
#include <stdio.h>
void main()
{
A();
printf("%d", n);
}
int n;
void A()
{
n = 10;
}
-
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NA
Correct Option: C
Compilation Error
main.c: In function ‘main’:
main.c:4:9: warning: implicit declaration of function ‘A’ [-Wimplicit-function-declaration]
A();
^
main.c:5:22: error: ‘n’ undeclared (first use in this function)
printf("%d", n);
^
main.c:5:22: note: each undeclared identifier is reported only once for each function it appears in
main.c: At top level:
main.c:8:10: warning: conflicting types for ‘A’
void A()
^
main.c:4:9: note: previous implicit declaration of ‘A’ was here
A();
^
- The name of the variable used in one function cannot be used in another function.
-
View Hint View Answer Discuss in Forum
NA
Correct Option: C
Since the scope of the variable declared within a function is restricted only within that function, the same name can be used to declare another variable in another function.
- A variable declared in a function can be used in main().
-
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NA
Correct Option: A
Since the scope of the variable declared within a function is restricted only within that function, so the above statement is false.
- Which of the following statement is false?
-
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NA
Correct Option: A
It is not an error if the variable is declared and not defined. For example – extern declarations.
