56. What will be the output of the following C code?
    

    #include <stdio.h>
        void main()
        {
            #define const int
            const min = 41;
            printf("%d", min);
        }
    

1. 1. const

   
   
   

   2. Compilation Error

   
   
   

   3. 41

   
   
   

   4. Runtime Error

   
   
   

   5. None of these

   
   
   

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1. View Hint View Answer Discuss in Forum

   NA

   Correct Option: C

   41

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57. What will be the output of the following C code?
    

    #include <stdio.h>
        void main()
        {
            #define min 85
            printf("%d", min);
        }
    

1. 1. Depends on compiler

   
   
   

   2. 85

   
   
   

   3. Compilation Error

   
   
   

   4. Runtime Error

   
   
   

   5. None of these

   
   
   

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1. View Hint View Answer Discuss in Forum

   NA

   Correct Option: B

   85

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58. What will be the output of the following C code?
    

    #include <stdio.h>
        void main()
        {
            #define min 56;
            printf("%d", min);
        }
    

1. 1. Depends on compiler

   
   
   

   2. 56

   
   
   

   3. Runtime Error

   
   
   

   4. Nothing

   
   
   

   5. Compilation Error

   
   
   

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1. View Hint View Answer Discuss in Forum

   NA

   Correct Option: E

   Compilation Error
   

   main.c: In function ‘main’:
   main.c:4:23: error: expected ‘)’ before ‘;’ token
            #define min 56;
                          ^
   main.c:5:22: note: in expansion of macro ‘min’
            printf("%d", min);
   

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59. What is the advantage of #define over const?

1. 1. Can have a pointer

   
   
   

   2. Reduction in the size of the program

   
   
   

   3. Data type is flexible

   
   
   

   4. All of above

   
   
   

   5. None of these

   
   
   

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1. View Hint View Answer Discuss in Forum

   NA

   Correct Option: C

   Data type is flexible

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60. What will be the output of the following C code?
    

    #include <stdio.h>
        int calc(int, int);
        #define calc(p, q) p / q + p
        int main()
        {
            int a = -17, b = 12;
            printf("%d ",calc(a + b, 12));
            #undef calc
            printf("%d\n",calc(a + b, 12));
        }
        int calc(int p, int q)
        {
            return p / q + p;
        }
    

1. 1. Compilation Error

   
   
   

   2. -17 12

   
   
   

   3. -21 -5

   
   
   

   4. Garbage value

   
   
   

   5. None of these

   
   
   

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1. View Hint View Answer Discuss in Forum

   NA

   Correct Option: C

   -21 -5

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