6. What will be the output of the following C code?
   

   #include <stdio.h>
       void main()
       {
           char *str = "PRAYAG";
           char *ptr = str;
           printf("%c %c", *ptr, str[2]);
       }
   

1. 1. P A

   
   
   

   2. PRAYAG P

   
   
   

   3. Garbage value

   
   
   

   4. Compilation Error

   
   
   

   5. None of these

   
   
   

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1. View Hint View Answer Discuss in Forum

   NA

   Correct Option: A

   P A

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7. What will be the output of the following C code?
   

   #include <,stdio.h>
       void main()
       {
           char *n= "KRISHANA";
           char *m = n + 3;
           printf("%c %c", *m, n[5]);
       }
   

1. 1. S A

   
   
   

   2. A S

   
   
   

   3. KRISHANA

   
   
   

   4. Compilation Error

   
   
   

   5. None of these

   
   
   

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1. View Hint View Answer Discuss in Forum

   NA

   Correct Option: A

   S A

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8. What will be the output of the following C code?
   

   #include <stdio.h>
       int main()
       {
           void *ptr1;
           int var[5] = {50, 60, 70, 80, 90};
           ptr1 = &var[3];
           int *ptr2 = &var[4];
           int m = (int*)ptr1 - ptr2;
           printf("%d\n", m);
       }
   

1. 1. 90

   
   
   

   2. Compilation Error

   
   
   

   3. Garbage value

   
   
   

   4. -1

   
   
   

   5. None of these

   
   
   

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1. View Hint View Answer Discuss in Forum

   NA

   Correct Option: D

   -1

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9. What will be the output of the following C code?
   

   #include <stdio.h>
       int main()
       {
           void *ptr1;
           int num[5] = {10, 20, 30, 40, 80};
           ptr1 = &num[4];
           int *ptr2 = &num[3];
           int R = ptr1 - ptr2;
           printf("%d\n", R);
       }
   

1. 1. 80

   
   
   

   2. 40

   
   
   

   3. 30

   
   
   

   4. 20

   
   
   

   5. Compilation Error

   
   
   

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1. View Hint View Answer Discuss in Forum

   NA

   Correct Option: A

   Compilation Error
   

   main.c: In function ‘main’:
   main.c:8:22: error: invalid operands to binary - (have ‘void *’ and ‘int *’)
            int R = ptr1 - ptr2;
   

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10. What will be the output of the following C code?
    

    #include <stdio.h>
        int main()
        {
            int *ptr1 = (int *)4;
            int *ptr2 = (int *)6;
            printf("%d", ptr1 + ptr2);
        }
    

1. 1. 4

   
   
   

   2. 6

   
   
   

   3. Compilation Error

   
   
   

   4. Garbage value

   
   
   

   5. 10

   
   
   

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1. View Hint View Answer Discuss in Forum

   NA

   Correct Option: C

   Compilation Error
   

   main.c: In function ‘main’:
   main.c:6:27: error: invalid operands to binary + (have ‘int *’ and ‘int *’)
            printf("%d", ptr1 + ptr2);
   

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