Data Types
- Which error are you likely to get when you run the following program in TC/TC++?
#include <stdio.h>
int main ( )
{
struct emp
{
char name[20];
float sal;
};
struct emp e[10];
int i ;
for (i = 0; i <= 9; i++)
{
printf ("Enter name and salary : ");
scanf ("%s %f" , e[ i ].name, &e[ i ].sal);
}
return 0 ;
}
-
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Floating point formats not linked
Just add the following function in your program. It will force the compiler to include required libraries for handling floating point linkages.static void force_fpf() /* A dummy function */
{
float x, *y; /* Just declares two variables */
y = &x; /* Forces linkage of FP formats */
x = *y; /* Suppress warning message about x */
}Correct Option: B
Floating point formats not linked
Just add the following function in your program. It will force the compiler to include required libraries for handling floating point linkages.static void force_fpf() /* A dummy function */
{
float x, *y; /* Just declares two variables */
y = &x; /* Forces linkage of FP formats */
x = *y; /* Suppress warning message about x */
}
- If the binary equivalent of 5.375 in normalized form is 0100 0000 1010 1100 0000 0000 0000 0000, what will be the output of the following program?
#include <stdio.h>
int main ( )
{
float a =5.375 ;
char *p ;
int i ;
p = (char *) &a ;
for (i = 0 ; i <= 3 ; i++)
printf("%02 X \n" , (unsigned char) p[ i ]);
return 0 ;
}
-
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Binary equivalent of 5.375 in normalized form is
0100 -> 4
0000 -> 0
1010 -> A
1100 -> C
0000 -> 0
0000 -> 0
0000 -> 0
0000 -> 0
Since the PC's (Intel processors) use " LITTLE ENDIAN" byte order, the higher order byte of number is stored in lowest address. The result is written from bottom to top.Correct Option: C
Binary equivalent of 5.375 in normalized form is
0100 -> 4
0000 -> 0
1010 -> A
1100 -> C
0000 -> 0
0000 -> 0
0000 -> 0
0000 -> 0
Since the PC's (Intel processors) use " LITTLE ENDIAN" byte order, the higher order byte of number is stored in lowest address. The result is written from bottom to top.
