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A room is mechanically ventilated through four air-conditioning ducts. The opening area of each duct is 0.35 sqm. The air velocity in the duct is 0.5 m/s. The temperature difference between the ambient air and supply air is 10°C. Volumetric specific heat of air is 1250 J/m³ °C. Assuming one Ton of refrigerat ion (TR) equals 3.5 kW, the cooling load of the room in TR will be _____________
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- 3.75 : 4.55
- 5.65 : 6.75
- 9.65 : 10.95
- 2.45 : 2.55
Correct Option: D
2.45 to 2.55
Total area of the duct = 4 × 0.35 = 1.4 m²
Total air volume in the room collected in 1 hr (3600 sec) = 1.4 × 0.5 × 3600 = 2520 m³
Total energy required = mcΔt = 2520 × 1250 × 10
= 31500000
| Joules Load in TR = | = 2.5 ton | |
| 3600 |
