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The estimated number of bricks (unit size: 250 mm × 125 mm × 75 mm) for laying one course of a 250 mm thick brick wall using rat-trap bond for a running length of 3.9 meter will be ___________
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- 36
- 46
- 56
- 66
Correct Option: A
36
Length required for the 2 Corners (4 bricks in nos.) = 2 x (75 + 75) = 300 mm = 0.3m
Length covered by the Penultimate headers laid on edge (2 bricks)= 0.25 m
Thus effective brick wall length in the centre = 3.9 – (0.3 + 0.25) = 3.35 m
The central part of the brick masonary will have a module of stretcher and header on edge (3 bricks in no.) taking up wall length = 75 + 250 = 325 mm = 0.325m
Now, 3.35/0.325 = 10.3 nearly 10 modules = 30 bricks
Total no. of bricks = bricks in the corners + bricks in the centre wall +bricks before the last corner = 4 + 30 + 2 = 36
Total bricks required = 36