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A housing project is proposed to be designed in a plot of 2 hectare. Maximum permissible FAR is 2. The share of the numbers of dwelling units (DU) for MIG, LIG and EWS is 1:2:3 having sizes of 55, 35 and 25 sq.m respectively. The maximum number of DU which can be accommodated in the plot is _______________
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- 1100
- 1200
- 1300
- 1400
Correct Option: B
(1200 to 1200)
Plot area = 2 hectare × 100 × 100
= 2 × 100 × 100 m²
Buildable area with 2 FAR = 2 × (2 × 100 × 100) m²
Total no of dwelling units = 1x + 2x + 3x = 6x
Area assigned for all MIG = (1x) × (55) m²
Area assigned for all LIG = (2x) × (35) m²
Area assigned for all EWS = (3x) × (25) m²
So, [(1x) × (55)] + [(2x) × (35)] +[(2x) × (35)]
= 2 × (2 × 100 × 100) m²
So, 200x = 40000
So, x = 200
The maximum number of
= 1x + 2x + 3x = 6x = 1200
