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At a particular locus, frequency of ‘A’ allele is 0.6 and that of ‘a’ is 0.4. What would be the frequency of heterozygotes in a random mating population at equilibrium?
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- 0.36
- 0.16
- 0.24
- 0.48
Correct Option: D
The mathematical expression to calculate allele frequency can be given as p + q = 1. Where p represents the frequency of dominant allele and q represents the frequency of recessive allele. The bionomial expression of Hardy Weinberg’s law to calculate genotype frequency is
p2 + 2pq + q2 = 1
where p2 = homozygous dominant
2pq = heterozygous dominant
q2 = homozygous recessive.
Frequency of heterozygous individuals = 2 × 0.6 × 0.4 = 0.48.