Home » Digital Circuits » Digital circuits miscellaneous » Question
  1. For a MOD-12 counter, FF hasa tpd = 60 ns. NAND gate has a tpd of 25 ns. The clock frequency is
    1. = 3.774 MHz
    2. > 3.774 MHz
    3. < 3.774 MHz
    4. = 4.167 MHz
Correct Option: A

For proper functioning, clock period should be equal to or greater than all the tpd
MOD – 12 – 4 FFs = 4 × 60 = 240 ns.
tpd = 25 ns.
∴ Total tpd = 265 ns
ƒc = 3.774 MHz



Your comments will be displayed only after manual approval.