Current I through resistance r in the circuit shown below,

Using KVL, we have

	V_a	+	V_a - V	+	V_a - V_b	= 0
	2R		2R		R

⇒ 4V_a = 2V_b + V

and	V_b - V_a	+	V_a	+	V_b	= 0
	R		2R		2R

⇒ 2V_b = V_a
∴ 3V_a = V
⇒ V_b = V/6
and I = V/12R

-	V
	12R

	V
	12R