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In the following sequential circuit, the initial state (before the first clock pulse) of the circuit is Q1Q0 = 00. The state (Q1Q0), immediately after the 333rd clock pulse is
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- 00
- 01
- 10
- 11
Correct Option: B
If the counter is Johnson (MOD-4) counter. Divide 333 by 4, so it will complete 83 cycle and remainder clock is 1, at the completion of cycles output’s in at Q1Q0 = 00 so, next at 333rd clock pulse output is at Q1Q0 = 01.