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The direct axis and quadrature axis reactances of a salient pole alternator are 1.2 p.u. and 1.0 p.u. respectively. The armature resistance is negligible. If this alternator is delivering rated KVA at upf and at rated voltage then its power angle is
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- 30°
- 45°
- 60°
- 90°
Correct Option: B
| tan δ = | ||
| Vt + Ia (xq sin φ - ra cos φ) |
For, φ = 0° [using p.f.],
I a = Vt = 1 pu
Xd = 1.2 pu,
Xq = 1pu,
ra = 0
we get, tan δ = 1
⇒ δ = 45°
