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A 220 V DC machine supplies 20 A at 200 V as a generator. The armature resistance is 0.2 ohm. If the machine is now operated as a motor at same terminal voltage and current but with the flux increased by 10%, then ratio of motor speed to generator speed is
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- 0.87
- 0.95
- 0.96
- 1.06
Correct Option: A
For Generator, E = V + Ia Ra
= 200 + 20 × 0.2 = 204 V
For Motor, V = E – Ia Ra
E = 200 – 20 × 0.2 = 196 V
∴ | = | × | |||
E2 | N2 | φ2 |
⇒ | = | × | ||||
196 | N2 | 11 |
and | = | = 0.87 | ||
N1 | 204 × 1.1 |