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Two transformers are to be operated in parallel such that they share load in proportion to their kVA ratings. The rating of the first transformer is 500 kVA and its pu leakage impedance is 0.05 pu. I f the rating of second transformer is 250 kVA, then its pu leakage impedance is
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- 0.20
- 0.10
- 0.05
- 0.025
Correct Option: B
| Per unit leakage impedance ∝ | ||
| kVA |
500 kVA × 0.05 = 250 kVA × x
| ∴ x = | × 0.05 = 0.10 | |
| 250 |
