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If corona loss on a particular system at 50 Hz is 1 kW/phase per km, then corona loss on the same system with supply frequency 25 Hz will be
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- 1 kW/phase/km
- 0·5 kW/phase/km
- 0·667 kW/phase/km
- none of these
Correct Option: C
Corona loss
| (P) = 241 × 10–5 | √ | (Vp - V0)², | ||
| δ | d |
where, ƒ = supply frequency
nOW P ∝ ƒ + 25
| ∴ | = | ||
| P2 | ƒ2 + 25 |
| or P2 = | |
| ƒ1 + 25 |
| or P1 = | × 1kW = /b>0.667kW/phase/km | |
| 75 |
