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The following data pertain to two alternators working in parallel and supplying a total load of 80 MW:
Machine 1: 40 MVA with 5% speed regulation
Machine 2: 60 MVA with 5% speed regulation
The load sharing between machines 1 and 2 will be
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P1 = P2 48 MW 48 MW - 40 MW 40 MW
- 30 MW 50 MW
- 32 MW 48 MW
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Correct Option: C
P1 + P2 = 80 MW
Now,
| ƒrated + | = ƒrated + | ||
| 100 | 100 |
or 40 – P1 = 60 – P2
Giving P1 – P2 = – 20
Also P1 + P2 = 80
∴ P1 = 30 MW
and P2 = 50 MW
