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A 5kVA, 400/2000 volt, 50Hz, 1 – φ transformer has primary and secondary leakage reactance each of 2.5 Ω . The total reactance in p.u. will be _____p.u.
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- 390 p.u.
- 39.0 p.u.
- 03.90 p.u.
- 0.390 p.u.
Correct Option: D
Let VA on both sides of the transfomer is 500 VA, i.e.
sb = 5000 VA,
Total reactance of the transfomer referred to primary
X1C = X1 + X2 | ![]() | ![]() | ² | |
N2 |
= 2.5 + 2.5 × | ![]() | ![]() | ² | |
200 |
= 2.5 + 10 = 12.5 Ω
Base voltage on primary side,
Vb1 = 400 V
Xpu = XΩ | ||
V²b1 |
Total p.u. reactance referred to primary
X1epu = X1e. | ||
V²b1 |
= 12.5 × | = 0.390 p.u. | |
(400)² |