If the sheath resistance is 2.14 Ω/km and that of

If the sheath resistance is 2.14 Ω/km and that of the conduct or is 0.1625 Ω/k m, and mutual inductance of the shealth is 3.13 × 10^–7 H/m. When the cable is 2 km long and supply is 50 Hz, the ratio of sheath loss to core loss of the cable will be_______

Sheath loss	=	R_s..M²ω²
Core loss	=	R(R²_s + M²ω²)

Here, Rs = 2 × 214
ω = 2πƒ = 2 × 3.14 × 50 = 314
M = 2 × 3.13 × 10^–7 × 10³
R = 2 × 0.1625 = 0.3250Ω

Sheath loss	=	(2 × 2.14) × (2 × 3.13 × 10^-4)² × 314²
Core loss	=	2 × 0.1625[(2 × 2.14)² + 314² × 6.26 × 10^-8]

= 0.0277.