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  1. The following arrangement consists of an ideal transformer and an attenuator which attenuates by a factor of 0.8. An ac voltage Vwx1 = l00V is applied across WX to get an open circuit voltage Vyz1, across YZ. Next, an ac voltageVyz2 = 100V is applied across YZ to get an open circuit voltage Vwx2 across WX. Then, Vyz1 VWX1/VWX2/VYZ2 are respectively.
    1. 125/100 and 80/100
    2. 100/100 and 80/100
    3. 100/100 and 100/100
    4. 80/100 and 80/100
Correct Option: B

1st case :
Vwx1 = 100 V

So, Vy'z1 =
M2
Vwx1 = 1.25 × 100 = 125V
M1

∴ Vy'z1 = Vy'z1 × x = 125 × 0.8 = 100 v.
∴ Vyz1 /Vwx1 = 100/100
2nd case :
Vyz2 = 100 V
∴ Vy't2 =
100
=
100
= 125 v
α0.8

Now, Vwx2 =
M1
Vy'z2 =
1
× 125 = 100 v
M21.25

∴ Vwx2/Vyz2 = 100/100
Vwx2 = 100V



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