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The following arrangement consists of an ideal transformer and an attenuator which attenuates by a factor of 0.8. An ac voltage Vwx1 = l00V is applied across WX to get an open circuit voltage Vyz1, across YZ. Next, an ac voltageVyz2 = 100V is applied across YZ to get an open circuit voltage Vwx2 across WX. Then, Vyz1 VWX1/VWX2/VYZ2 are respectively.
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- 125/100 and 80/100
- 100/100 and 80/100
- 100/100 and 100/100
- 80/100 and 80/100
Correct Option: B
1st case :
Vwx1 = 100 V
So, Vy'z1 = | Vwx1 = 1.25 × 100 = 125V | |
M1 |
∴ Vy'z1 = Vy'z1 × x = 125 × 0.8 = 100 v.
∴ Vyz1 /Vwx1 = 100/100
2nd case :
Vyz2 = 100 V
∴ Vy't2 = | = | = 125 v | ||
α | 0.8 |
Now, Vwx2 = | Vy'z2 = | × 125 = 100 v | ||
M2 | 1.25 |
∴ Vwx2/Vyz2 = 100/100
Vwx2 = 100V