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Consider a stator winding of an alternator with an internal high-resistance ground fault. The currents under the fault condition are as shown in the figure given below. The winding is protected using a differential current scheme with current transformers of ratio 400/5 A as shown in the figure given below. The current through the operating coil is

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- 0.1875 A
- 0.2 A
- 0.375 A
- 60 kA
Correct Option: C

| I1 = 200 × | ||
| 400 |
| and I2 = 250 × | ||
| 400 |
| ∴ I2 - I1 = | (250 - 220) | |
| 400 |
| = | × 30 = | = 0.375 A | ||
| 400 | 8 |