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  1. The three-stage Johnson counter as shown in figure is clocked at a constant frequency of ƒc from the starting state of Q2Q1Q0 = 101. The frequency of output Q2Q1Q0 will be

    1. ƒc/8
    2. ƒc/6
    3. ƒc/3
    4. ƒc/2
Correct Option: D


We see that 1 0 1 repeat after every two cycles, hence frequency will be ƒc/2 .



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