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The given figure shows wein bridge connection for frequency measurement. C and R are variables and ganged together. For balanced condition the expression for frequency is ƒ = 1/2πCR when

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- R1 = R2
- R1 = 2R2
- R1 = R2/2
- R1 = 3R2
Correct Option: C
From the balance equation,
| R1 | ![]() | R + | ![]() | = R2 | R. | ||
| jωC | |||||||
| jωC | R + | ||||||
| jωC | |||||||
| or | = | |||
| jωC | (jωCR + 1) |
or R1 (– C²ω²R² + 1 + 2 jωCR) = jR2CωR
or 2CωRR1 = CωRR2
| ∴ R1 = | |
| 2 |
and – C²ω²R² + 1 = 0,
| or ω = | |
| RC |
| or ƒ = | |
| 2πRC |

