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A 230 V, 10 A, single-phase energymeter makes 90 revolutions in 3 minutes at half load rated voltage and unity pf. If the meter constant is 1800 revolutions /kWh, then its error at half load will be
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- 13.04% slow
- 13.04% fast
- 15% slow
- 15% fast
Correct Option: C
Energy consumed as indicate by energy meter
| = | = 0.05 kWh | |
| 1800 |
Actual energy consumed
| = 200 × | ![]() | ![]() | × 1 × | ![]() | ![]() | × 10-3 = 0.0575 kWh | ||
| 2 | 60 |
∴ Error = 0.0500 – 0.0575 = – 0.0075 kWh
| Hence meter is slow by = | × 100 = 15% | |
| 0.0500 |

