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A simple d.c. potentiometer is to be standardised by keeping the sidewire setting at 1. 0813 V. If by mistake, the setting is at 1.0138 V and the standardisation is made to obtain a source voltage of 1.0318 V, then the reading of the potentiometer will be
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- 1.0138 V
- 1.0183 V
- (1.0138)²/ 1.0183 V
- (1.0138)² V
Correct Option: C
The setting of the potentiometer is at 1.0138 instead of 1.0813. Therefore, working current in the slide wise is more than what it would have been if the setting was at 1.0813,
i.e. correct value for applied voltage of 1.0813V,
I = 1.0813, Ic = 1.0138
It the setting is at 1.01138 and the applied voltage is also 1.0138 and the applied voltage is also 1.0138, the standardisation is then correct. (Statement of the problem appears ambiguous).
