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An analog voltmeter uses external multiplier settings. With a multiplier setting of 20 kΩ, it reads 440 V and with a multiplier setting of 80 kΩ, it reads 352 V. For a multiplier setting of 40 kΩ, the voltmeter reads
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- 371 V
- 383 V
- 394 V
- 406 V
Correct Option: D
Let resistance of voltmeter be R kΩ 
| V = |  |  | = 20 + 440 | |
| R |
| V = 352 + | | | = 80 | |
| R |
Solving equations (1) and (2), we get
V = 480; R = 220
| ∴ VL = | × 220 = 406 V | |
| 40 + 220 |
