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What is the output of the following C code? Assume that the address of x is 2000 (in decimal) and an integer requires four bytes of memory ?
int main()
{
unsigened int x[4] [3] = {(1,2,3), {4,5,6}, {7, 8, 9}, {10, 11, 12}};
printf(“%u, %u, %u”, x+3, *(x+3),
*(x+2)+3);
}
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- 2036, 2036, 2036
- 2012, 4, 2204
- 2036, 10, 10
- 2012, 4, 6
- 2036, 2036, 2036
Correct Option: C
NA