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What is printed by the following C program?
int f (int x, int * py, int ** ppz)
{
int y, z;
**ppz + = 1; z = *ppz;
*py + = 2; y = *py;
x + = 3;
return x + y + z;
}
void main ()
{
int c, *b, **a,
c = 4; b & c; a = & b
printf(“%d”, f(c, b, a));
}
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- 18
- 19
- 21
- 22
- 18
Correct Option: B
The program gets executed in the following manner
Graphical Representation
Now, considering
int y, z;
**ppy + = 1; z = *ppz = 6
*py + = 2; y = *py = 6
x = 4 + 3 = 7
return x + y + z;
and
c = 4; b & c; a = &b;
printf (“%d”, f(c, b, a)),
From the code,
The output is printed as 6 + 6 + 7 = 19.
