Direction: The computer system has an L1 L2 cache, an L2 cache and a main memory unit connected as shown below. The block size in L1 cache is 4 words. The block size in L2 cache is 16 words. The memory access times are 2 ns, 20 ns and 200 ns, for L1 cache, L2 cache and main memory unit respectively.
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When there is a miss in L1 cache and a hit in L2 cache, a block is transferred from L2 cache to L1 cache. What is the time taken for this transfer?
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- 2 ns
- 20 ns
- 22 ns
- 88 ns
- 2 ns
Correct Option: D
A block to access in L2 cache requires 20 neno seconds and 2 seconds to place in 4 cache the block size in L1 cache is 4 words and there are total 16 words, so total time is = 4 * (20 + 2) = 88
