Consider a disk pack with 16 surfaces, 128 tracks per surface

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Consider a disk pack with 16 surfaces, 128 tracks per surface and 256 sectors per track. 512 byte of data are stored in a bit serial manner in a second. The capacity of the disk pack and the number of bits required to specify a particular section in the disk are respectively

1. 256 Mbyte, 19 bit
2. 256 Mbyte, 28 bit
3. 512 Mbyte, 20 bit
4. 64 Gbyte, 28 bit

Correct Option: A

The formula used is
Total disk size is given by = Number of surfaces × Number of tracks × Number of sectors × Capacity of each sector. Therefore from the given data, we get
Total disk size = 16 × 128 × 256 × 512 byte
= 2⁸ × 2²⁰ = 2⁸ megabyte = 256 MB
Total number of sectors = 16 × 128 × 256 byte = 2¹⁹ byte