-
Consider a small two-way set-associative cache memory, consisting of four blocks. For choosing the block to be replaced, use the Least Recently Used (LRU) scheme. The number of cache misses for the following sequence of block addresses is 8, 12, 0, 12, 8
-
- 2
- 3
- 4
- 5
- 2
Correct Option: C
We have 4 blocks and 2 blocks in a set.
⇒ There are 2 sets,
since the lowest bit of block address is used for indexing into the set. So, 8, 12, and 0 first miss in cache with 0 replacing 8 and then 12 will be hit in cache and 8 again miss. So totally 4 misses.