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A sender uses the Stop-and-Wait ARQ protocol for reliable transmission of frames. Frames are of size 1000 bytes and the transmission rate at the sender is 80 Kbps (1Kbps = 1000 bits/second). Size of an acknowledgement is 100 bytes and the transmission rate at the receiver is 8Kbps. The one-way propagation delay is100 milliseconds. Assuming no frame is lost, the sender throughput is ________ bytes/second.
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- 1.5 Kbps
- 2.5 Kbps
- 12.5 Kbps
- 20.5 Kbps
Correct Option: B
2500
Frame size (L) = 1000 bytes
Sender side Bandwidth (Bs) = 80 kbps
Acknowledgement (LA) = 100 bytes
Receiver side Bandwidth (BR) = 8kbps
Tp = 100 ms
| n = | ||
| Tx + Tack + 2Tp |
| Tx(msg) = | = | = 100 ms | ||
| Bs | 10 × 103 BPS |
| TA(Ack) = | = | = 100 ms | ||
| BR | 1 × 103 BPS |
Tp = 100 ms
| ∴ Channel Utilization = | = | = | |||
| Tx + Tack + 2Tp | 100 ms + 100 ms + 200 ms | 4 |
| ∴ Throughput = η × B = | × 10 × 103 = 2.5 Kbps (or 2500 bps) | |
| 4 |
