-
Consider two hosts X and Y, connected by a single direct link of rate 106 bits/sec. The distance between the two hosts is 10,000 km and the propagation speed along the link is 2 × 108 m/sec. Host X sends a file of 50,000 bytes as one large message to host Y continuously. Let the transmission and propagation delays be p milliseconds and q milliseconds, respectively. Then the values of p and q are
-
- p = 50 and q = 100
- p = 50 and q = 400
- p = 100 and q = 50
- p = 400 and q = 50
- p = 50 and q = 100
Correct Option: D
As given that B (Bandwidth) = 106 bits/sec
D (Distance) = 10,000 Km = 104 × 103 m = 107 m
V (Velocity) = 2 × 108 m/s
L(Data size) = 50,000 bytes = 50000 × 8 bits
| Transmission time (P) = | ||
| Bandwidth |
| = | ||
| 106 bits / sec |
P = 400 m / sec
| Propagation time (V) = | ||
| Velocity |
| = | ||
| 2 × 108 m / sec |
= 50 × 105 - 8
= 50 × 10-3 sec
(q = 50 m/sec.)
Hence option (d) is correct.
