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In a token ring network, the transmission speed is 107 bps and the propagation speed is 200 m/ms. The 1-bit delay in this network is equivalent to
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- 500 m of cable
- 200 m of cable
- 20 m of cable
- 50 m of cable
- 500 m of cable
Correct Option: C
107 bits require time = 1 s
⇒ 1 Bit require = 1/107 s (unitary method)
⇒ | = 10-6 / 10 s = | ms | ||
10 × 106 | 10 |
Now, 1 ms = 200 m cable
⇒ 1/10 ms = 20 m cable