The theoretical oxygen dmenad of a 0.001 mol/L glucose solution is
180 mg/L
192 mg/L
90 mg/L
96 mg/L
Correct Option: B
Glucose: C6H12O6 0.001 mol/L of glucose = 180 × 0.001 g/litre = 180 mg/L glucose From the equation 180 parts glucose need 192 parts oxygen. ∴ 180 mg/L glucose need 192 mg/L oxygen