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Water requirements miscellaneous

  1. A waste water stream (flow = 2m³/s, ultimate BOD = 90 mg/l) is joining a small river (flow = 12 m³/s, ultimate BOD = 5 mg/ l). Both water streams get mixed up instantaneously. Crosssectional area of the river is 50 m². Assuming the deoxygenation rate constant, k = 0.25.day, the BOD (in mg/l) of the river water, 10 km downstream of the mixing point is
    1. 1.68
    2. 12.63
    3. 15.46
    4. 1.37
Correct Option: C

BOD of mixture, Y =
(2 × 90) + (12 × 5)
= 17.143 g/m³
2 × 12

KD = 0.434 × k1
= 0.434 × 25 = 0.1085
Velocity of stream =
14
= 0.28 m/s
50

Time taken =
10 km
= 9.921 hours
0.28 m/s

Yt = Yo (1 – 10–kt)
= 17.143 (1 – 10–0.1085 × 9.921) = 15.7 mg/l



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