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x + 2y + z = 4
2x + y + 2z = 5
x – y + z = 1
The system of algebraic given below has
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- A unique solution of x = 1, y = 1 and z = 1
- only the two solutions of (x = 1, y = 1, z = 1) and (x = 2, y = 1, z = 0)
- infinite number of solutions
- No feasible solution
- A unique solution of x = 1, y = 1 and z = 1
Correct Option: C
ρ [A] = [ A / B ] = 2
But ρ [A] = ρ [A / B ] < Number of variables.
ρ < n
So we have infinite number of solutions.
