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Engineering Mathematics Miscellaneous

Engineering Mathematics

  1. The area enclosed between the parabola y = x2 and the straight line y = x is
    1. 1
      8

    2. 1
      6

    3. 1
      3

    4. 1
      2

Correct Option: B

Given equations are
y = x2 ...(i)
y = x ...(ii)
From equations (i) and (ii)
x 2 – x = 0
⇒ x(x – 1) = 0
⇒ x = 0, 1

Area enclosed = dydx = ∫1x = 0 dxy = x²y = x dy

= [y]y = x²y = xdx = (x² - x) dx

=
x3
-
x2
1
320

=
1
-
1
=
2 - 3
= -
1
3266




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