Direction: The complete solution of the ordinary differential equation
+ p | + qy = 0 is | |||
dx2 | dx |
y = c1e-x + c2e-3x
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Which of the following is a solution of the differential equation d2y + p dy + (q + 1)y = 0 ? dx2 dx
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- e-3x
- xe-x
- xe-2x
- x2e-2x
- e-3x
Correct Option: C
+ p | + (q + 1)y = 0 | |||
dx2 | dx |
∴ D2 + pD + (q + 1) = 0
⇒ D2 + 4D + 4 = 0
Since, p = 4, q = 3, therefore
⇒ D = | = -2 | |
2 |
Hence, it's solution is, = xeDx = xe–2x