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Consider a truss PQR loaded at P with a force F as shown in the figure.
The tension in the number QR is
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- 0.5 F
- 0.63 F
- 0.73 F
- 0.87 F
- 0.5 F
Correct Option: B
TPQ cos 40° + TPR cos 60° + F = 0
and TPQ sin 40° = TPR sin 60°
From these equations
TPQ and TPR can be found in terms of F
Now at Q, T TQR = TPQ cos 45°
Solving these equations, we get TQR = 0.63 F
