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A heat reservoir at 900 K is brought into contact with the ambient at 300 K for a short time. During this period 9000 kJ of heat is lost by the heat reservoir. The total loss in availability due to this process is
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- 18000 kJ
- 9000 kJ
- 6000 kJ
- None of these
- 18000 kJ
Correct Option: C
| Entropy change for hot reservoir ∆Sh = | = | = -10 kJ/ k | ||
| T | 900 |
| Energy gain in cold reservoir ∆Sc = | = | = +30 kJ/ k | ||
| T | 300 |
Loss in availability = T0[∆Sc + ∆Sh]
⇒ Loss in availability = 300(30 – 10) = 300(20) = 6000 kJ
