An engine working on air standard Otto cycle has a cylinder

An engine working on air standard Otto cycle has a cylinder diameter of 10 cm and stroke length of 15 cm. The ratio of specific heats for air is 1.4. If the clearance volume is 196.3 cc and the heat supplied per kg of air per cycle is 1800 kJ/kg, the work output per cycle per kg of air is

Given: V_c = V₂ = 196.3 cm³ = 0.0001963 m³ stroke

volume V_s =	π	D² × L =	π	(10)² × 15 = 1178.09 cc
	4		4

Compression ratio, r =	V_s + V_c
	V_c

Compression ratio, r =	1178.09 + 196.3	= 7
	196.3

η_otto = 1 -	1
	r^{γ - 1}

η_otto = 1 -	1
	(7)^{1.4 - 1}

η_otto = 1 -	1	= 0.5408
	(7)^0.4

Now ,

η_otto =	work output	=	W
	Heat supplied		Q_s

0.5408 =	work output	⇒ work output = 973.5 kJ
	1800