The divergence of the vector field 3xzî + 2xyĵ

Home » Engineering Mathematics » Engineering Mathematics Miscellaneous » Question

The divergence of the vector field 3xzî + 2xyĵ - yz2k̂ at a point (1, 1, 1) is equal to

1. 7
2. 4
3. 3
4. 0

Correct Option: C

F = 3xzi + 2xyj - yz²k

∴ div = ∇ . F =	δ	(3xz) +	δ	-	δ	(yz²)
	δx		δy		δz

= 3z + 2x –2yz
At point (1, 1, 1),
divergence = 3 + 2 –2 = 3