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Steady two-dimensional heat conduction takes place in the body shown in the figure below. The normal temperature gradients over surface P and Q can be considered to be uniform. The temperature gradient δT/δt at surface Q is equal to 10 K/m. Surfaces P and Q are maintained at constant temperatures as shown in the figure, while the remaining part of the boundary is insulated. The body has a constant thermal conductivity of 0.1 W/mK.
The values of δT and δT at surface P are δy δx
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δT = 20 K/m δT = 0 K/m δx δy -
δT = 0 K/m δT = 10 K/m δx δy -
δT = 10 K/m δT = 10 K/m δx δy -
δT = 0 K/m δT = 20 K/m δx δy
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Correct Option: D
Direction of heat flow is always normal to surface of constant temperature
So for surface P1, dT/dx = 0
From energy conservation,
Heat rate at P = Heat rate at Q
0.1 × 1 | = 0.1 × 2 × | dy | P | dx | Q |
⇒ | = 20 K/m | dy |