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A 100 W electric bulb was switched on in a 2.5 m × 3 m × 3 m size thermally insulated room having a temperature of 20°C. The room temperature at the end of 24 hours will be
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- 321 °C
- 341 °C
- 450°C
- 470°C
Correct Option: D
Heat generated by bulb = 100 × 24 × 60 × 60 Joule.
∴ Heat dissipated = ρ × V × Cv × (T – 20)
⇒ 100 × 24 × 60 × 60 = 1.24 × 9 × 2.5 × 3 × Cv (T – 20)
⇒ T = 450º