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  1. A forged steel link with uniform diameter of 30 mm at the centre is subjected to an axial force that varies from 40 kN in compression to 160 kN in tension. The tensile (Su), yield (Sy) and corrected endurance (Se) strengths of the steel material are 600 MPa, 420 MPa and 240 MPa respectively. The factor of safety against fatigue endurance as per Soderberg's criterion is
    1. 1.26
    2. 1.37
    3. 1.45
    4. 2.00
Correct Option: C

Fatigue endurance, σen = 240 MPa
A = π/4 × (30)2 × 706.5 × 10–6 m2
Soderberg’s equation is

1
=
σm
+
σa
hσyσen.f

Now Fm =
160 + 40
= 100 kN
2

∴ σm =
Fm
=
100 kN
= 141.54 MPa
A706.5 × 10 -6

and Fa =
160 - 40
= 60 kN
2

∴ σa =
160 - 40
= 84.93 MPa
60 × 10 3

1
=
141.54
+
84.93
h420240

or h = 1.45



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